Calculate Joule-Thomson Coefficient

Calculates the Joule-Thomson coefficient μ_JT = (∂T/∂P)_H, which describes the temperature change of a gas during isenthalpic (constant enthalpy) expansion. For real gases, this coefficient can be positive (cooling) or negative (heating) depending on temperature and pressure. The inversion temperature separates these regimes.

Use Cases:

• Model non-equilibrium processes in markets
• Analyze expansion/contraction dynamics
• Study irreversible processes in trading
• Temperature-pressure analogies in finance
• Throttling process models

Formula: μ_JT = (1/C_p)[T(∂V/∂T)_P - V]

For Van der Waals gas: μ_JT ≈ (2a/RT - b)/C_p

Credits: 5 credits per request (Pro Tier) [Tier: ENTERPRISE, Credits: 10]

POST /quantlib/physics/thermodynamics/joule-thomson

cURL

ideal_gas

curl --request POST \ --url https://api.fincept.in/quantlib/physics/thermodynamics/joule-thomson \ --header 'Content-Type: application/json' \ --header 'X-API-Key: <api-key>' \ --data ' { "temperature": 300, "pressure": 101325, "Cp": 29.1, "a": 0, "b": 0 } '

200

{
  "success": true,
  "data": {
    "joule_thomson_coefficient": 0.00000234
  }
}

Authorizations

X-API-Key · string · header · required

API key for authentication. Get your key at https://api.fincept.in/auth/register

Body

application/json

temperature · number · default: 300

Temperature (Kelvin)

Example:

300

pressure · number · default: 101325

Pressure (Pa)

Example:

101325

Cp · number · default: 29.1

Heat capacity at constant pressure (J/(mol·K))

Example:

29.1

a · number · default: 0

Van der Waals parameter a (Pa·m⁶/mol²)

Example:

0.1

b · number · default: 0

Van der Waals parameter b (m³/mol)

Example:

0.01

Response

200

application/json

Joule-Thomson coefficient calculated successfully

success · boolean

Example:

true

data · object

Show child attributes